Circular Motion of swing ride

  • Thread starter keemosabi
  • Start date
  • #1
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Homework Statement


A "swing" ride at a carnival consists of chairs that are swung in a circle by 12.0 m cables attached to a vertical rotating pole, as the drawing shows. (θ = 55.5°) Suppose the total mass of a chair and its occupant is 192 kg.


(a) Determine the tension in the cable attached to the chair.
N
(b) Find the speed of the chair.
m/s


5-19alt.gif



Homework Equations



Fc = mv^r

The Attempt at a Solution


Ty = Fg
Ty = 9.8 * 192
Ty = 1881.6 N
T = 1881.6/sin 34.5
T = 3321.997

Fc = Tx
Fc = 3321.997 cos 34.5
Fc = 2737.74
Fc = mv^2/r
2737.74 = 192(v^2)/12
v = 13.081

The first part was right but what did I do wrong in the second part?
 

Answers and Replies

  • #2
tiny-tim
Science Advisor
Homework Helper
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Hi keemosabi! :smile:
Fc = mv^2/r
2737.74 = 192(v^2)/12
erm … 12 isn't the radius. :redface:
 
  • #4
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