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Circular Motion of swing ride

  1. Nov 23, 2008 #1
    1. The problem statement, all variables and given/known data
    A "swing" ride at a carnival consists of chairs that are swung in a circle by 12.0 m cables attached to a vertical rotating pole, as the drawing shows. (θ = 55.5°) Suppose the total mass of a chair and its occupant is 192 kg.


    (a) Determine the tension in the cable attached to the chair.
    N
    (b) Find the speed of the chair.
    m/s


    [​IMG]


    2. Relevant equations

    Fc = mv^r

    3. The attempt at a solution
    Ty = Fg
    Ty = 9.8 * 192
    Ty = 1881.6 N
    T = 1881.6/sin 34.5
    T = 3321.997

    Fc = Tx
    Fc = 3321.997 cos 34.5
    Fc = 2737.74
    Fc = mv^2/r
    2737.74 = 192(v^2)/12
    v = 13.081

    The first part was right but what did I do wrong in the second part?
     
  2. jcsd
  3. Nov 23, 2008 #2

    tiny-tim

    User Avatar
    Science Advisor
    Homework Helper

    Hi keemosabi! :smile:
    erm … 12 isn't the radius. :redface:
     
  4. Nov 23, 2008 #3
    Is it 12 sin 55.5?
     
  5. Nov 23, 2008 #4
    yep!
     
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