(adsbygoogle = window.adsbygoogle || []).push({}); Circular Motion--Quick Question

A ferris wheel has a radius of 15 m and a period of 60 s is shown below. Find the Fnet at points B and D if the rider has a mass of 60 kg.

Ok, so this is a solved problem from a physics text book.

This is the solution given in the text book.

At B

Fnet = Fc - Fg (since they act in the same direction)

At D

Fnet = Fc + Fg (since they act in the different directions)

Solution

At B:

Fnet = Fc - Fg = 686 N - 9.9 N = 676 N

At D:

Fnet = Fc + Fg = 686 N + 9.9 N = 696 N

They found Fc by using 4pi^2rm/T^2

Heres where the problem arises.

I think that this solution is wrong.

How I solved it:

I took the direction in wich tension acts as positive.

So at B(at top of the wheel)

Net force= Fc+Fg

And at D(at the bottom of the wheel)

Net force= Fc-Fg

Am I right?

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# Homework Help: Circular Motion-Quick Question

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