Circular Motion--Quick Question A ferris wheel has a radius of 15 m and a period of 60 s is shown below. Find the Fnet at points B and D if the rider has a mass of 60 kg. Ok, so this is a solved problem from a physics text book. This is the solution given in the text book. At B Fnet = Fc - Fg (since they act in the same direction) At D Fnet = Fc + Fg (since they act in the different directions) Solution At B: Fnet = Fc - Fg = 686 N - 9.9 N = 676 N At D: Fnet = Fc + Fg = 686 N + 9.9 N = 696 N They found Fc by using 4pi^2rm/T^2 Heres where the problem arises. I think that this solution is wrong. How I solved it: I took the direction in wich tension acts as positive. So at B(at top of the wheel) Net force= Fc+Fg And at D(at the bottom of the wheel) Net force= Fc-Fg Am I right?