- #1
Kushal
- 438
- 1
circular motion please
a particle is slightly displaced from rest at the top of a fixed smoothsphere of radius r. Find the the vertical height through which the particle descends befor eleaving the sphere.
f = (mv^2)/r
w = mg
i thought that the particle would leave the sphere when the centripetal force is less than the contact force. the contact force is equal to the x component of weight. from the angle, i found the height, i.e. cos (theta) = h/r h is the adjacent, and r is the hypotenuse.i took the angle between the negative x-axis and the actual weight vector as theta.
i can't find the answer and I'm afraid I've messed up the concepts
Homework Statement
a particle is slightly displaced from rest at the top of a fixed smoothsphere of radius r. Find the the vertical height through which the particle descends befor eleaving the sphere.
Homework Equations
f = (mv^2)/r
w = mg
The Attempt at a Solution
i thought that the particle would leave the sphere when the centripetal force is less than the contact force. the contact force is equal to the x component of weight. from the angle, i found the height, i.e. cos (theta) = h/r h is the adjacent, and r is the hypotenuse.i took the angle between the negative x-axis and the actual weight vector as theta.
i can't find the answer and I'm afraid I've messed up the concepts