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[SOLVED] Circular motion
two spheres of equal mass are attached to a light wire of negligible mass of length 3 m ,as shown in the diagram attatched, the spheres and the rod are whirled about point O at a constant rate.
F=ma
a= 4pi^2r/T^2
Find:
(the tension in the wire between spheres X and Y)/(Tension in the wire between sphere Y and O)
Finding the "Tension in the wire between sphere Y and O":
acceleration = (4pi^2(1))/(T^2) since r=1m
From f=ma
there are two masses flying around so ill let the mass equal to 2m.
therefore F= 2m x (4pi^2)/t^2
I don't know how to approach the rest of the problem. I don't even know if I've done it correctly so far.
Homework Statement
two spheres of equal mass are attached to a light wire of negligible mass of length 3 m ,as shown in the diagram attatched, the spheres and the rod are whirled about point O at a constant rate.
Homework Equations
F=ma
a= 4pi^2r/T^2
Find:
(the tension in the wire between spheres X and Y)/(Tension in the wire between sphere Y and O)
The Attempt at a Solution
Finding the "Tension in the wire between sphere Y and O":
acceleration = (4pi^2(1))/(T^2) since r=1m
From f=ma
there are two masses flying around so ill let the mass equal to 2m.
therefore F= 2m x (4pi^2)/t^2
I don't know how to approach the rest of the problem. I don't even know if I've done it correctly so far.
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