1. The problem statement, all variables and given/known data a test tube rotates in a centrifuge with a period of 1.2x10^-3s. The bottom of the test tube travels in a circular path of radius .15 m. with the centripetal force on a 2.00x10^-8kg amoeba at the bottom of the tube. 3. The attempt at a solution ac=v^2/r=(4pi^2r)/T cross multiplied and got. v^2x(1.2x10^-3)=4pi^2x(1.5^2) divided and solved for velocity and I got. V=27.21 then fc=(m2v^2)/r fc=(2x10^-8)x(27.210^2)/.15 fc=9.87x10^5???? supposed to be 8.22x10^2 THanks.