# Circular Motion

1. Oct 13, 2009

### joemama69

1. The problem statement, all variables and given/known data

A shaft is set up in the vertical direction. Two strings are attached to a mass m, the shaft is rotates so that the tangential velocity of m is 3.10 m/s

a) Find tension of string 1 & 2

2. Relevant equations

3. The attempt at a solution

First I found the acceleration

a = v2/r = 3.12/1.25 = 2.48 m/s2

Fa = ma = 1.75*2.48 = 4.34 N

I then took it into components

$$\sum$$Fx = Fa - T1sin$$\theta$$ - T2sin$$\theta$$ = 0 = 4.34 - T1sin$$30$$ - T2sin$$30$$

$$\sum$$Fy = T1cos30 - mgT2cos30 = 0

are these correct i would just solve for the Ts here on after
1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

#### Attached Files:

• ###### Microsoft PowerPoint - Presentation1.pdf
File size:
17.9 KB
Views:
30
2. Oct 14, 2009

### joemama69

i thin Fy = T1 - T2 - mgcos30 = 0