- #1

cheerspens

- 92

- 0

## Homework Statement

A man sitting on the edge of his seat on a Ferris Wheel has a mass of 50.0 kg. The Ferris Wheel has a radius r=30m and the ferris wheel completes a single revolution every 20 seconds. Find the force between the man and the chair.

## Homework Equations

F

_{NET}=ma

F

_{g}=mg

[tex]\tau[/tex]=2[tex]\pi[/tex]r/v

a=v

^{2}/r

## The Attempt at a Solution

I found the force of gravity on the man to be 490N. I think the period is 0.05rev/sec so I set up the [tex]\tau[/tex] equation to be 0.05=2[tex]\pi[/tex](30)/v. I solved for V however and get 3769.91 m/s. It seems like too big of a number. This then gives me a very large acceleration of 473740.71m/s

^{2}.

I need to solve for a to plug into my F

_{NET}equation in order to find the force on the chair on man.

What am I doing wrong to get these large numbers?