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Circular motion

  1. Dec 12, 2004 #1
    A satellite is orbiting the earth at an rate of 96 minutes. The radius of the earth and the mass is known. How do I calculate how high above earth the satellite is orbiting?

    I tried to use formula a= 4*(3.14^2)*(r+6380)/t

    But I dont have the acceleration, and If I would use newtons law of universal gravitation, I dunno where to start. Can someone help me?
  2. jcsd
  3. Dec 12, 2004 #2
    T = 2xPi SquareRoot(r^3/GM)
    Where G = 6.67 x 10^-11 and M is the mass of the earth, use r = radius..
    You have the time, 96 x 60 for seconds..
    Now, you're solving for r.
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