Circular Motion

  • #1

Homework Statement


A .8 kg lead ball is whirled on the end of a string 5 meters long. When the ball passes through point A at the top of the path, the tension in the string is 4.96 N.
What is the speed of the bob at point A?
*NOTE - POINT A is at the top of the circle...

Homework Equations


F=ma
F=m(v2/r)

The Attempt at a Solution


F=m(v2/r)
v = √(F*r)/m

V = √(4.96*5)/.8
V = 5.57 m/s

DOESN'T WORK...!
 

Answers and Replies

  • #2
rock.freak667
Homework Helper
6,230
31
At the top of the circle, what are the forces acting and in what directions do they act (up or down) ?

The resultant of these forces is equal to the centripetal force mv2/r
 
  • #3
Umm force of weight and that's all... and it acts down.
But what does that do?
 
  • #4
249
26
Umm force of weight and that's all... and it acts down.
But what does that do?
Not just weight. Another force acts on it too. You've mentioned it in the problem itself.
 
  • #5
20,445
4,353
Umm force of weight and that's all... and it acts down.
But what does that do?
Have you drawn a free body diagram showing the forces acting on the ball, or do you feel you have advanced beyond the point where you need to use free body diagrams?
 

Related Threads on Circular Motion

  • Last Post
Replies
8
Views
694
Replies
3
Views
4K
  • Last Post
Replies
18
Views
632
  • Last Post
Replies
7
Views
1K
  • Last Post
Replies
3
Views
1K
  • Last Post
Replies
3
Views
1K
  • Last Post
Replies
2
Views
849
  • Last Post
Replies
1
Views
1K
  • Last Post
Replies
0
Views
1K
  • Last Post
Replies
1
Views
1K
Top