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## Homework Statement

A .8 kg lead ball is whirled on the end of a string 5 meters long. When the ball passes through point A at the top of the path, the tension in the string is 4.96 N.

What is the speed of the bob at point A?

*NOTE - POINT A is at the top of the circle...

## Homework Equations

F=ma

F=m(v

^{2}/r)

## The Attempt at a Solution

F=m(v

^{2}/r)

v = √(F*r)/m

V = √(4.96*5)/.8

V = 5.57 m/s

DOESN'T WORK...!