A .8 kg lead ball is whirled on the end of a string 5 meters long. When the ball passes through point A at the top of the path, the tension in the string is 4.96 N.
What is the speed of the bob at point A?
*NOTE - POINT A is at the top of the circle...
The Attempt at a Solution
v = √(F*r)/m
V = √(4.96*5)/.8
V = 5.57 m/s