Circular orbital velocity.

  • Thread starter m00npirate
  • Start date
  • #1
50
0
If you are at the distance R from a planet and you want to achieve a circular orbit your velocity must be Sqrt[Gm/R] perpendicular to the radius vector.

But what if you launch at an angle (ie no longer perpendicular to the radius)? Is it still possible to achieve a circular orbit if the perpendicular component is still Sqrt[Gm/R]?
 

Answers and Replies

  • #2
mathman
Science Advisor
7,877
453
Mt guess is that you will end up with some sort of ellipse.
 
  • #3
Meir Achuz
Science Advisor
Homework Helper
Gold Member
3,529
110
You will definitely have a non-circular ellipse.
 

Related Threads on Circular orbital velocity.

Replies
9
Views
1K
Replies
7
Views
3K
  • Last Post
Replies
9
Views
2K
Replies
24
Views
2K
Replies
5
Views
969
Replies
5
Views
1K
  • Last Post
Replies
1
Views
2K
Replies
6
Views
2K
  • Last Post
Replies
23
Views
343
Top