1. The problem statement, all variables and given/known data A solid cylinder of mass 10 kg is pivoted about a frictionless axis through the center O. A rope wrapped around the outer radius R1 = 1.0 m, exerts a force F1 = 5.0 N to the right. A second rope wrapped around another section of radius R2 = 0.50 m exerts a force F2 = 6.0 N downward. How many radians does the cylinder rotate through in the first 5.0 seconds, if it starts from rest? 2. Relevant equations 3. The attempt at a solution I did find the torque for each force, with the counterclockwise force being positive. so T(1) = (1.0 m)(5m) = 5 N*m T(2) = (0.5 m)(6.0 N) = 3 N*m so I figured out that the net torque would be 2 N*m in the clockwise direction. But i don't know what to do with this. Thank you so much!