I had x^2+y^2=Ae^x, how can i find out the cirle pass (0,1) and perpendicular to that cirle ?
Perpendicular to what circle? x2+ y2= Aex is NOT a circle!
sorry, it is curve not circle ? But I foun answer, I do sqare root of y and find y' and let it be a tangent's coeficent, and put it in a of y=ax+b, i found equation of y.
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