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Cirle quation

  1. Oct 15, 2004 #1
    I had x^2+y^2=Ae^x, how can i find out the cirle pass (0,1) and perpendicular to that cirle ? :frown:
  2. jcsd
  3. Oct 15, 2004 #2


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    Perpendicular to what circle? x2+ y2= Aex is NOT a circle!
  4. Oct 15, 2004 #3
    sorry, it is curve not circle ? But I foun answer, I do sqare root of y and find y' and let it be a tangent's coeficent, and put it in a of y=ax+b, i found equation of y. :smile: :smile:
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