1. The problem statement, all variables and given/known data A Civil War cannon fires a cannonball at 900 ft/s. If the cannon is aimed 5 degrees above the horizontal, find the time that the cannonball is in the air. A Civil War cannon fires a cannonball at 900 ft/s. If the cannon is aimed 5 degrees above the horizontal, find the height that the cannonball reaches. 2. Relevant equations Sin=opp/hyp y=y0+v0t+1/2a(t^2) 3. The attempt at a solution First I found the vertical velocity using sine. 900 sin s=78 ft/s . Next I found the time using the vertical velocity. v0=78 ft/s a=-32.2 ft/s v=0 t=(v-v0)/a 0-78/-32.2 t=-78/-32.2 t=4.8 s. 4.8 seconds should be the answer to the first problem. Next, I used y=y0+v0t+1/2a(t^2) to find the height the cannonball reached. y=0+78(4.8)+1/2(-32.2)(4.8) y=374.4+1/2(154.56) y=377.4-77.28=300.12 Height=300 ft. Are my answers correct? Thanks in advance!