(adsbygoogle = window.adsbygoogle || []).push({}); NEED HELP!!! with permutation proof

Sorry for any confusion the question I have is:

Show that a permutation with odd order must be an even permutation.

The order of a permutation of a finite set written in disjoint cycle form

is the least common multiple of the lengths of the cycles.

This is what I have worked out so far:

Lete= epsilon

LetB= a permutation

Letk= any integer

Now sayB^(2k+1) = e. WhereB^(2k+1)is an odd permutation.

ThenB^(2k)= B^(-1).

ButB^(2k) = B^(k)^2is even.

I would really appreciate some help in putting this

proof together in a more coherent fashion.

I am very confused. Thanks

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# Clarification of Permuatation Question

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