Clarification on phasor math

  • Thread starter tempneff
  • Start date
  • #1
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I'm told that [itex](e^{j \omega})^{-2} = e^{-2\omega}[/itex]...?
I thought by the property [itex](a^b)^c=a^{bc}[/itex] it should equal [itex]e^{-2j\omega}[/itex]
What am I missing?
 

Answers and Replies

  • #2
Simon Bridge
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Who told this to you and in what context?
 

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