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Clarification on phasor math

  1. Dec 8, 2014 #1
    I'm told that [itex](e^{j \omega})^{-2} = e^{-2\omega}[/itex]...?
    I thought by the property [itex](a^b)^c=a^{bc}[/itex] it should equal [itex]e^{-2j\omega}[/itex]
    What am I missing?
     
  2. jcsd
  3. Dec 8, 2014 #2

    Simon Bridge

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    Who told this to you and in what context?
     
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