# Clarification on phasor math

1. Dec 8, 2014

### tempneff

I'm told that $(e^{j \omega})^{-2} = e^{-2\omega}$...?
I thought by the property $(a^b)^c=a^{bc}$ it should equal $e^{-2j\omega}$
What am I missing?

2. Dec 8, 2014

### Simon Bridge

Who told this to you and in what context?