- #1
tictactony
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Homework Statement
A camper hangs a 22 kg pack between two trees, using two separate pieces of rope of different lengths, as shown in the figure below. (I don't know how to post the picture but I'm sure you can visualize two ropes and two trees with angle measures 71 left and 28 right)
Homework Equations
Weight=mg
The Attempt at a Solution
I'm pretty sure I know how to do this problem because I've done it before with easier numbers. I'm actually getting quite frustrated and I'm on my last guess wondering what the heck I'm doing wrong.
Using T1 as the tension in the left rope I calculated: T1*sin(71)=T1y
T2 tension in the right: T2*sin(28)=T2y
then I know both these y components have to add up to 215.6 N because (22kg)(9.8m/s^2) yields the gravitational force on the pack.
Next I did the x components and got:
T1*cos(71)=T1x
T2*cos(28)=T2x
Since the pack is stationary I know the x components have to be equal.
I'm left with a system of equations and after eliminating T2 I'm left with
T1=(215.6)/(sin(28)) / ((sin(71))/(sin(28))+((cos(71))/(cos(28)))
T1=(215.6)/(sin(28)) / (sin(71)+tan(28)*cos(71))
T1=766.696 which I KNOW is incorrect because that exceeds the weight of the pack
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