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**1. The problem statement, all variables and given/known data**

A camper hangs a 22 kg pack between two trees, using two separate pieces of rope of different lengths, as shown in the figure below. (I don't know how to post the picture but I'm sure you can visualize two ropes and two trees with angle measures 71 left and 28 right)

**2. Relevant equations**

Weight=mg

**3. The attempt at a solution**

I'm pretty sure I know how to do this problem because I've done it before with easier numbers. I'm actually getting quite frustrated and I'm on my last guess wondering what the heck I'm doing wrong.

Using T1 as the tension in the left rope I calculated: T1*sin(71)=T1y

T2 tension in the right: T2*sin(28)=T2y

then I know both these y components have to add up to 215.6 N because (22kg)(9.8m/s^2) yields the gravitational force on the pack.

Next I did the x components and got:

T1*cos(71)=T1x

T2*cos(28)=T2x

Since the pack is stationary I know the x components have to be equal.

I'm left with a system of equations and after eliminating T2 I'm left with

T1=(215.6)/(sin(28)) / ((sin(71))/(sin(28))+((cos(71))/(cos(28)))

T1=(215.6)/(sin(28)) / (sin(71)+tan(28)*cos(71))

T1=766.696 which I KNOW is incorrect because that exceeds the weight of the pack

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