I Classical Mechanics Goldstein Eq3.14 help please

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1. Dec 7, 2017

bengeof

how is md^2r/dt^2 . dr/dt = d/dt (1/2 m (dr/dt)^2 )

Thank You

2. Dec 7, 2017

Chain rule.

3. Dec 7, 2017

bengeof

Can you work it out for me explicitly ?

4. Dec 7, 2017

Ibix

Can you state the chain rule? Can you apply it to the time derivative of $(dr/dt)^2$?

5. Dec 7, 2017

6. Dec 7, 2017

bengeof

2dr/dt . . is that right ?

7. Dec 7, 2017

8. Dec 7, 2017

PeroK

That makes no sense. The LHS is the answer to the derivative on the RHS. There's nothing to work out on the left.

9. Dec 7, 2017

bengeof

okay Got it. Thank you so much !!

10. Dec 8, 2017

Dr.D

The rest of Goldstein may present difficulties.