1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Classical scattering

  1. Sep 13, 2011 #1
    I have spent lot of time trying to understand scattering from Goldstein but in vain. The general equation of an orbit is,

    1/r = K[1 + e*cos(θ - θ')] where e=eccentricity
    I refer to a sentence in goldstein which says, if θ'=pi then θ = 0 corresponds to the periapsis. What is θ' in the case of hyperbolic orbit? As far as the general equation is concerned, θ' is one of the turning angles of the orbit but in scattering there is only one turning angle which corresponds to the periapsis.
    Then the equation becomes,
    1/r = K[1 - e*cos(θ)]
    Please help.
  2. jcsd
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook

Can you offer guidance or do you also need help?
Draft saved Draft deleted