Please check my work.(adsbygoogle = window.adsbygoogle || []).push({});

Using the first uncertainty principle:

[tex]

\Delta x \Delta k \sim 1

[/tex]

derive the second uncertainty principle:

[tex]

\Delta \omega \Delta t \sim 1

[/tex]

My work:

[tex]

\Delta x \Delta k \sim 1

[/tex]

[tex]

\frac {\Delta x} {\Delta t} = V \Rightarrow \Delta x = V \Delta t

[/tex]

[tex]

V \Delta t \Delta k \sim 1

[/tex]

[tex]

V_\textrm {group} = \frac {\Delta \omega} {\Delta k}

[/tex]

[tex]

\frac {\Delta \omega} {\Delta k} \Delta t \Delta k \sim 1

[/tex]

[tex]

\frac {\Delta k} {\Delta k} \Delta \omega \Delta t \sim 1

[/tex]

[tex]

\Delta \omega \Delta t \sim 1

[/tex]

What do you think?

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Classical uncertainty principles

**Physics Forums | Science Articles, Homework Help, Discussion**