Hello, I am stuck on classifying the points with this DE...=\ xy''+(x-x^3)y'+(sin x)y=0 The solution says (sin x)/x is infinitely differentiable...so x=0 is an ordinary point? I was taught...if P(xo)=0, then xo is a singular point. Here P(x)=x...so x=0. So, what I don't get is the "infintely differentiable" part. Does it have something to do with the convergent Tayloe Series about x=0? And what does that mean? I got another example here... x^2(y'')+(cos x)y'+xy=0 Here P(x)=0 so x=0 is a singular point. It's also a irregular singular point because as x->0 (cos x)/x goes to infinity. How come here x=0 is a singular point here? Thank you.