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Clausius Clapeyron Equation

  1. Nov 17, 2013 #1

    Qube

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    Gold Member

    1. The problem statement, all variables and given/known data

    Determine the vapor pressure of water at 50 degrees C. The molar heat of vaporization of water is 40.7 kJ/mol.

    2. Relevant equations

    Clausius-Clapeyron equation.

    Clausi1.gif

    3. The attempt at a solution

    P1 = 760 mm Hg
    T1 = 373 K

    P2 = ?
    T2 = 323 K

    ln (P2/760) = ln P2 - ln 760 = -(40700/8.31)(1/323 - 1/373). I'm taking the change in temperature (delta T, or final minus initial temperature, and accordingly I put a negative out in front of the right side of the equation).

    ln P2 = 4.6

    e^4.6 = P2 = 100 mm Hg (approximately).

    Is this correct?
     
  2. jcsd
  3. Nov 17, 2013 #2

    Borek

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    Staff: Mentor

    Tables give 92.51 mm Hg, so you are reasonably close.
     
  4. Nov 17, 2013 #3

    Qube

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    Gold Member

    Thank you :-)!
     
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