For those who don't want to download the diagram, G and D are on either side of the lightning rod at A at equal distances from it, and H and E are on either side of the lightning rod at B at equal distances from it.Referring to Fig 1
There is a boxcar travelling along train tracks at a constant velocity.
In the box car there are two lightening rods located at point A and B
There are a series of points G, D, H, E marked on the floor of the boxcar.
So, clock X is to the right of lightning rod B at point E, and clock Y is to the right of lightning rod A at point D.length GA = length DA = length HB = length EB
In the boxcar there is a person named Dash
In the boxcar there are two identical clocks X and Y. The clocks stop when they are struck by photons from lightening
Dash is at rest wrt the boxcar as are the clocks
External to the boxcar is Still Bill who is not at rest wrt the boxcar
Dash positions the clocks at points D and E as shown and then synchronises clock X and Y. Dash now concludes that the clocks are synchronised within his frame.
The light will only reach his eyes simultaneously if the strikes occurred simultaneously in Still Bill's frame, i.e. if T0 referred to Still Bill's time coordinate. If the strikes occurred simultaneously in Dash's frame, then the light from the strikes will reach Still Bill's eyes at different moments.At time T0 Still Bill is a distance L from points A and B. As Still Bill is equidistant from points A and B the photons from A and B will strike his eyes simultaneously and he will conclude that the lightening bolts struck simultaneously.
But here you are assuming something incompatible with the above. If the strikes occurred simultaneously in Still Bill's frame, then they occurred non simultaneously in Dash's frame, therefore the time on the clocks X and Y will be different.Theory states that the photons from the lightening bolts travel at C and for spheres about points A and B
As length DA = length EB I don’t think I need to drive the fact that the time on the clocks X and Y will be the same. Going off the clocks Dash will also conclude that the lightening struck simultaneously.
In a standard explanation of simultaneity using train cars and lightning strikes, they always specifically state which frame the strikes are simultaneous in (usually the Earth's rest frame). You can't just say two strikes happen at A and B because it isn't enough information to answer your questions, it might be they were simultaneous in Still Bill's frame (Still Bill sees light from both strikes at same moment, Dash's clocks show different readings when light reaches them), it might be that they were simultaneous in Dash's frame (Still Bill sees light from both strikes at different moments, Dash's clocks show same reading when light reaches them), or it might be they weren't simultaneous in either frame (Still Bill sees light at different moments and Dash's clocks show different readings). These are all physically different scenarios, and they are all physically possible.I agree T0 is too vague replace it with lightening bolts strike at points A and B. Dash and Still Bill want to know if they were simultaneous or not.
I dont assume anything different from any explanation you will find for simultenaiety.
Yes, in Still Bill's frame. However, in Still Bill's frame these two clocks are not synchronized, so they will show different times when the light hits them despite the fact that the light hits them simultaneously in this frame.referring to fig 1 Just a question. If Still Bill percieves the bolts as simultaneous will the photons from A strike clock Y simultaneously as the photons from B to clock X? from Still Bills perspective