The answer given was the set of all positive even integers, but I was thinking that the smallest subset would be the given element and the identity element (0 in this case) so that A = {0,2}...wouldn't this be more accurate?

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The answer given was the set of all positive even integers, but I was thinking that the smallest subset would be the given element and the identity element (0 in this case) so that A = {0,2}...wouldn't this be more accurate?

A set S is closed under a binary operator + iff for all x, y in S, x + y is in S.

A = {0, 2} isn't closed under addition because the definition is not satisfied. We can find a counter example where x and y are both in S, but x + y is not. The counter example is with x = 2 and y = 2.

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S = {0, 2} doesn't work since 2+2=4 is not in S.

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