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Closed Sets

  1. Oct 19, 2005 #1
    How do you do this proof??? Isn't it already obvious given the definition? I have no idea how to go about writing it down. :confused: If someone could help me with this, I would really appreciate it. Thanks :) Sorry I had to write it in such a messy way.

    Define the closure of A as A closure = (x|for every open rectangle u containing x, intersection of u and A not equal to 0)

    a) Show that A closure = A union bdA

    b) Prove that bdA = intersection of A closure and (R^n-A) closure = bd(R^n-A)
     
    Last edited: Oct 20, 2005
  2. jcsd
  3. Oct 19, 2005 #2

    Tom Mattson

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    Can we see your proof before we answer?
     
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