(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

5 A closed wire loop in the form of a square of side 4.0 cm is mounted with its plane horizontal. The loop has a resistance of 2.0 x 10-3Ω, and negligible self-inductance. The loop is situated in a magnetic field of 0.70 T, directed vertically downwards. When the field is switched off, it decreases to zero at a uniform rate on 0.80 s. What is:

a) the current induced in the loop,

b) the energy dissipated in the loop during the change in the magnetic field?

c) Show on a diagram, justifying your statement, the direction of the induced current.

2. Relevant equations

a) can someone please check this...

[tex]\phi[/tex]=BA

[tex]\phi[/tex]=1.12*10^{-3}Wb

V=N[tex]\Delta[/tex][tex]\phi[/tex]/[tex]\Delta[/tex]t

V=1.4*10^{-3}V

I=V/R

I=0.7A

b) this one im not sure about

given P=Vi and power is energy over time i derived:

energy =VIt is that energy dissipated or something like total energy????

Energy =7.84*10^{-4}J

c) see the attachment. sorry about the terrible pic - I dont have a scanner - Conventional current.

Ps. Im not asking anyone to sit down with a calculator and check my work, I just want to know if my procedure is right...\

Thanks

3. The attempt at a solution

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# Homework Help: Closed wire loop

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