Closest Approach of 6 MeV Alpha Particle on Fe Nucleus

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In summary, the closest approach of a 6 MeV alpha particle on a Fe nucleus refers to the minimum distance between the two during a collision. This can be calculated using the Rutherford scattering formula and can cause the alpha particle to change direction or lose energy due to the repulsive force from the nucleus. The closest approach can also disrupt the structure of the Fe nucleus, leading to nuclear reactions or even breakage. Studying this phenomenon is important for understanding nuclear forces and has practical applications in fields such as nuclear energy and medical imaging.
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Civilian2
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What is the closest distance of approach of a 6 MeV alpha particle colliding with a nucleus of iron (56 26 Fe)?
 
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Use the law of conservation of total energy.Kinetic & potential of electric/electrostatic nature.I guess u can assume the iron nucleus to be at rest b4 & after the collision (scattering),though it's a dreadful approximation (mass ratio:1/14).

Daniel.
 
  • #3


The closest distance of approach of a 6 MeV alpha particle colliding with an iron nucleus would depend on the specific experimental conditions and the trajectory of the particle. However, it can be estimated using the Rutherford scattering formula, which describes the scattering of charged particles off of a central Coulomb potential.

Assuming the alpha particle is approaching head-on towards the iron nucleus, the closest distance of approach can be calculated using the following formula:

d_min = (q_1q_2)/4πε_0E

Where d_min is the closest distance of approach, q_1 and q_2 are the charges of the alpha particle and iron nucleus respectively, ε_0 is the permittivity of free space, and E is the kinetic energy of the alpha particle.

Plugging in the values for the charges and kinetic energy, we get:

d_min = (2*79*1.6*10^-19)/(4π*8.85*10^-12*6*10^6)

= 2.9*10^-14 meters

This is a very small distance, on the order of 10^-14 meters, which is consistent with the size of atomic nuclei. It is also worth noting that this value is only an estimate and the actual closest distance of approach may vary depending on the exact experimental conditions.
 

Related to Closest Approach of 6 MeV Alpha Particle on Fe Nucleus

1. What is the closest approach of a 6 MeV alpha particle on a Fe nucleus?

The closest approach is the minimum distance between the alpha particle and the Fe nucleus during a collision.

2. How is the closest approach of a 6 MeV alpha particle on a Fe nucleus calculated?

The closest approach can be calculated using the Rutherford scattering formula, which takes into account the kinetic energy of the alpha particle, the charge of the nucleus, and the distance between them.

3. What happens to the alpha particle during the closest approach to the Fe nucleus?

During the closest approach, the alpha particle experiences a strong repulsive force from the positively charged nucleus. This can cause the alpha particle to change direction or lose energy.

4. How does the closest approach of a 6 MeV alpha particle on a Fe nucleus affect the nucleus?

The closest approach can disrupt the structure of the Fe nucleus, causing it to undergo nuclear reactions or even break apart.

5. Why is studying the closest approach of alpha particles on nuclei important?

Studying the closest approach helps us understand the fundamental forces that govern the behavior of particles at the nuclear level. It also has practical applications in fields such as nuclear energy and medical imaging.

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