- #1
sroderi
- 2
- 0
ok so it has been a few years since I have worked on things like this and I am needing some help
I have a CO2 tank that weighs 22.17 oz's when full. There is 9 oz's of CO2 in the tank. The problem I am working on is that I need to find out how far the tank will go when the safety burst disk goes off as well as its velocity. The exit hole is around 1.9 mm and it goes off at 3000 psi. The volume of the tank is around 19.5865 in^3
I started off by doing (3000 psi) X (.00439 in^2) which gave me the force coming out of the jet. I then divided it by the total weight of the tank which gave me an acceleration of 9.52622 ft/s^2. I questioned this considering the pressure, acceleration, and weight will be decreasing and changing I just didn’t know how to do it the right way.
I then started working on trying to find out how long it would take to empty the tank. I used Boyle law (P1V1=P2V2) = (2982.3*19.865in^3) = (14.7*(X)) When I found X I was going to divide it by the flow rate to give me the time it takes to empty.
Well flow rate is Velocity X Area so I am having problems finding the velocity of the CO2 leaving the tank. I tried messing with Bernoulli’s equation but had a hard time with the density of the CO2 which I was assuming a temperature of 20 C anything around that will work.
Once I find that velocity of the CO2 I can find the discharge time. I think I can put it in the equation (D=.5a(t)^2) to get distance
I may be way off it has been a long time since I worked on this stuff so if anyone could help me with this I would greatly appreciate it
Thanks
I have a CO2 tank that weighs 22.17 oz's when full. There is 9 oz's of CO2 in the tank. The problem I am working on is that I need to find out how far the tank will go when the safety burst disk goes off as well as its velocity. The exit hole is around 1.9 mm and it goes off at 3000 psi. The volume of the tank is around 19.5865 in^3
I started off by doing (3000 psi) X (.00439 in^2) which gave me the force coming out of the jet. I then divided it by the total weight of the tank which gave me an acceleration of 9.52622 ft/s^2. I questioned this considering the pressure, acceleration, and weight will be decreasing and changing I just didn’t know how to do it the right way.
I then started working on trying to find out how long it would take to empty the tank. I used Boyle law (P1V1=P2V2) = (2982.3*19.865in^3) = (14.7*(X)) When I found X I was going to divide it by the flow rate to give me the time it takes to empty.
Well flow rate is Velocity X Area so I am having problems finding the velocity of the CO2 leaving the tank. I tried messing with Bernoulli’s equation but had a hard time with the density of the CO2 which I was assuming a temperature of 20 C anything around that will work.
Once I find that velocity of the CO2 I can find the discharge time. I think I can put it in the equation (D=.5a(t)^2) to get distance
I may be way off it has been a long time since I worked on this stuff so if anyone could help me with this I would greatly appreciate it
Thanks