A force of 10N is applied downward at an angle of 30 deg with respect to the horizontal on a block. There is friction between the block and the floor and the block remains stationary. M=2kg
(a) What is the magnitude of the normal force acting on the block?
(b) The coefficient of friction between the floor and block is μ = 0.8. What is the magnitude of the frictional force acting on the block?
Fn = mg + 10sin30
Fn(mu) = Fk
The Attempt at a Solution
I got part A -- Fn = mg + 10sin30 = 19.6 + 5.0 = 24.6
But for part B, I thought it would be 24.6*.8 = 19.7, but according to the answer key, it should be 8.7.