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## Homework Statement

A force of 10N is applied downward at an angle of 30 deg with respect to the horizontal on a block. There is friction between the block and the floor and the block remains stationary. M=2kg

(a) What is the magnitude of the normal force acting on the block?

(b) The coefficient of friction between the floor and block is μ = 0.8. What is the magnitude of the frictional force acting on the block?

## Homework Equations

Fn = mg + 10sin30

Fn(mu) = Fk

## The Attempt at a Solution

I got part A -- Fn = mg + 10sin30 = 19.6 + 5.0 = 24.6

But for part B, I thought it would be 24.6*.8 = 19.7, but according to the answer key, it should be 8.7.

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