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Introductory Physics Homework Help
What is the coefficient of friction in a child pulling a sled up an incline?
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[QUOTE="Sprockets, post: 5054230, member: 548617"] Sorry Simon I meant to say mgcos(15) is equal to the normal force, its on my diagram. AdityaDev, I have the force along the incline as mgsin(15). I think what's really confusing me is that 37 degree angle where is it? "rope inclined at 37 degrees to the horizontal," to me says that there is a rope that a kid is pulling on, on top of the 15 degree incline the angle between the rope and the horizontal is 37 and since the kid is pulling on this block that's on top of this 15 degree incline the tension must be parallel to the slope of the 15 degree incline. Like what i tried to draw. [/QUOTE]
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Introductory Physics Homework Help
What is the coefficient of friction in a child pulling a sled up an incline?
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