1. The problem statement, all variables and given/known data A force of 22.0 N is required to start a 2.6 kg box moving across a horizontal concrete floor. 1)If the 22.0 N force continues, the box accelerates at 0.50 m/s2. What is the coefficient of kinetic friction? 2. Relevant equations coefficient=Ff/Fn Fn=mg 3. The attempt at a solution To find Ff, I used F=ma and got (2.6)*(0.50) and got 1.3. I subtracted the 1.3 from the 22.0 N and got 20.7 then i used Ff/Fn which was 20.7/25.48 and got .812 is that correct?