(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A force of 22.0 N is required to start a 2.6 kg box moving across a horizontal concrete floor.

1)If the 22.0 N force continues, the box accelerates at 0.50 m/s2. What is the coefficient of kinetic friction?

2. Relevant equations

coefficient=Ff/Fn

Fn=mg

3. The attempt at a solution

To find Ff, I used F=ma and got (2.6)*(0.50) and got 1.3. I subtracted the 1.3 from the 22.0 N and got 20.7 then

i used Ff/Fn which was 20.7/25.48 and got .812 is that correct?

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# Homework Help: Coefficient of force

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