A train moves on a straight track at y degrees to the horizontal. The mass of the train is 1000kg. during its motion the train moves under the action of a variable propulsive force, p newtons, and a constant resultant forceR newtons
(a) during the first stage of motion, the train moves horizontally with acceleration 0.25 ms-2. In this stage the value of P is 1200 sow that R = 950.
The Attempt at a Solution
resolved the force in direction of train got;
1200 - R - sinyo = 1000 x 0.25
950 = R + sinyo
so how can R = 950, is sinyo taken as < 0.5??