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Coefficient of friction help please!

  • #1

Homework Statement



A train moves on a straight track at y degrees to the horizontal. The mass of the train is 1000kg. during its motion the train moves under the action of a variable propulsive force, p newtons, and a constant resultant forceR newtons

(a) during the first stage of motion, the train moves horizontally with acceleration 0.25 ms-2. In this stage the value of P is 1200 sow that R = 950.

Homework Equations



F=ma mabey

The Attempt at a Solution



resolved the force in direction of train got;

1200 - R - sinyo = 1000 x 0.25
950 = R + sinyo

so how can R = 950, is sinyo taken as < 0.5??
help please!
 

Answers and Replies

  • #2
89
0
In part (a) of the question, when it says the train is moving horizontally, it means that y=0o.
 
  • #3
aaaaah you ledgend, cannot believe i didnt see that - i really am a physics goon!
 

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