1. The problem statement, all variables and given/known data A skier traveling 12.6 m/s reaches the foot of a steady upward 15.2° incline and glides 12.0 m up along this slope before coming to rest. What was the average coefficient of friction? 2. Relevant equations 3. The attempt at a solution D = 12m Velocity initial = 12.3 m/s V final = 0 m/s Angle = 15.2° incline Use the equation Vf^2 = Vi^2 + 2*a*d Find a 0 = 12.3^2 + 2*a*12 2*a*12 = -12.3^2 Divide both sides by 2*12 a = 6.30375 m/s^2 Force parallel = mass * g * sin θ Force normal = mass*g* cos θ Friction Force = µ * mass*g* cos θ Going up an incline 2 forces decrease your velocity Force parallel and Friction, so we add these 2 forces to find the total force decreasing your velocity. Since these forces decrease your velocity they are negative. a = 6.30375 m/s^2 ∑ Forces = mass * acceleration (-mass * g * sin θ) + -(µ * mass*g* cos θ) = mass * 6.30375 Notice mass cancels (- g * sin 15.2°) + (-µ * g* cos 15.2° ) = 6.30375 6.30375 = -2.57 + -9.457 µ 6.30375 = -12.027 µ µ = 0.524 But the answer is incorrect. Can someone please tell me where I messed up?