1. Mar 11, 2010

### mparsons06

1. The problem statement, all variables and given/known data

A skier traveling 12.6 m/s reaches the foot of a steady upward 15.2° incline and glides 12.0 m up along this slope before coming to rest. What was the average coefficient of friction?

2. Relevant equations

3. The attempt at a solution

D = 12m
Velocity initial = 12.3 m/s
V final = 0 m/s
Angle = 15.2° incline

Use the equation Vf^2 = Vi^2 + 2*a*d
Find a

0 = 12.3^2 + 2*a*12
2*a*12 = -12.3^2

Divide both sides by 2*12
a = 6.30375 m/s^2

Force parallel = mass * g * sin θ
Force normal = mass*g* cos θ
Friction Force = µ * mass*g* cos θ

Going up an incline 2 forces decrease your velocity
Force parallel and Friction, so we add these 2 forces to find the total force decreasing your velocity. Since these forces decrease your velocity they are negative.
a = 6.30375 m/s^2

∑ Forces = mass * acceleration
(-mass * g * sin θ) + -(µ * mass*g* cos θ) = mass * 6.30375
Notice mass cancels

(- g * sin 15.2°) + (-µ * g* cos 15.2° ) = 6.30375
6.30375 = -2.57 + -9.457 µ
6.30375 = -12.027 µ
µ = 0.524

But the answer is incorrect. Can someone please tell me where I messed up?

2. Mar 11, 2010

### aim1732

By how much? Your initial velocity suddenly went from 12.6 m/s to 12.3m/s.

3. Mar 11, 2010

### mparsons06

I just recalculated my mistake, and I got $$\mu$$ = 0.549.

Does that seem right to you?

4. Mar 11, 2010

### aim1732

(- g * sin 15.2°) + (-µ * g* cos 15.2° ) = 6.30375
6.30375 = -2.57 + -9.457 µ
6.30375 = -12.027 µ
µ = 0.524

But the answer is incorrect. Can someone please tell me where I messed up?[/QUOTE]

In your original calculation you have put the net acceleration +ve which isn't the case as forces are along the acceleration.

5. Mar 11, 2010

### mparsons06

So, I'm slightly confused. Do you mean it should be:

(- g * sin 15.2°) + (-µ * g* cos 15.2° ) = 6.615
6.615 = -2.57 + 9.457 µ
6.615 = 6.887 µ
µ = 0.961

I'm drawing a blank. =/

6. Mar 11, 2010

### aim1732

No I meant the opposite. It should be
-g*sin15.2 - µ*g*cos15.2 = -6.615.
One more thing, why are you always adding the the terms on left when there is a unknown
µ with one of the terms. Like here(this is yours):
6.615 = -2.57 + 9.457 µ
6.615 = 6.887 µ​
[/CENTER]

I noticed it in the first post too.

7. Mar 11, 2010

### mparsons06

So I redid it:

-g*sin15.2 - µ*g*cos15.2 = -6.615.
-2.572 - 9.457 µ = -6.615
-9.457 µ = -4.043
µ = 0.4275

Is that correct?

8. Mar 11, 2010

### aim1732

Yes looks good to me.