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Coefficient of Friction

  1. Oct 28, 2013 #1
    1. Here is the problem http://i.imgur.com/WH0Z4ko.png


    So I've set up a Free Body Diagram and I think I have it right. I have the two Forces of Weight (8.82N and 21.27N), the force of 12.8 that is pulling the .9kg box, and then the Force Normal (just the opposites of the two Forces of Weight). I didn't really understand how the prof. was using the coefficient of friction in the problem and I'm not sure how to start with this problem.
     
  2. jcsd
  3. Oct 28, 2013 #2

    462chevelle

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    Gold Member

    I would start by finding the Ff
    then you can see how much force is actually being applied horizontally at any given direction
     
  4. Oct 28, 2013 #3
    Thanks!
     
  5. Oct 28, 2013 #4

    462chevelle

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    Gold Member

    did you figure it out?
     
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