SOLVED 1. The problem statement, all variables and given/known data Suppose the coefficient of kinetic friction between m1 and the plane in the figure is [tex]\mu[/tex]k= 0.24 m1 = m2 = 2.5kg As m2 moves down, determine the magnitude of the acceleration of m1 and m2 given [tex]\Theta[/tex] = 26. 2. Relevant equations F=ma 3. The attempt at a solution m2g = (2.5kg)(9.8m/s2)= 24.5N 24.5 - T = 2.5a (2.5kg)(9.8m/s2)sin26 = 18.6827N (2.5kg)(9.8m/s2)cos26 = 15.8495N (.24)(15.8495N) = 3.80388N T - 18.6827 - 3.80388 = 2.5a 24.5 - T = 2.5a (-18.6827-3.80388+24.5)= (2.5a+2.5a) 2.01342 = 5a a=.402 m/s2 Why isn't my answer correct did I do any miscalculations?