A 12kg block is released from rest on an inclined plane with angle 35. Acceleration of the block is 1.23457 The acceleration of gravity is 9.8m/2^2. What is the coefficient of kinetic friction for the incline? I found the normal force (12*9.8*cos35)=96.33228 Fnet=ma=12*1.23457=14.81484 Ff=N-Fnet=81.51744 So, I thought mu=Fnet/N=0.8462, but that answer is apparently wrong. Any ideas?