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Coefficient of Restitution, Conservation of Momentum

  1. Apr 16, 2008 #1
    Using conservation of momentum:

    [itex] 4.\frac{3}{2} + 0 = 4v_A + v_B [/itex]
    [itex] 6 = 4v_A + v_B [/itex]

    Coefficient of restitution:

    [itex] \frac{2(v_B - v_A)}{3} = e [/itex]
    [itex] 2v_B - 3e = 2v_A [/itex]

    [itex] 6 = 2(2v_B - 3e) + v_B [/itex]

    Where do I go from here...? Thanks.
  2. jcsd
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