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Coefficient of Restitution

  1. Nov 26, 2014 #1
    1. The problem statement, all variables and given/known data
    I drop a ball downwards vertically onto a smooth table. The coefficient of restitution is 0<e<1. The ball rebounds upwards vertically with speed x. What is the time taken between the time that the ball was dropped to its nth rebound?

    Also, what is the time taken before the ball becomes stationary?

    2. Relevant equations
    e = speed of separation/speed of approach
    Constant acceleration formulae

    3. The attempt at a solution
    Say the ball rises to a height h after the first rebound. Then h = x^2/(2g). The time taken to reach this height is t = x/g using the quadratic formula...
     
  2. jcsd
  3. Nov 26, 2014 #2

    haruspex

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    Yes.
    That cannot be right because the right hand side has dimension time-squared.

    With what speed does it hit the floor the second time? What will be the next rebound speed?
     
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