Coefficient of Static Friciton

In summary, the conversation is about a problem involving a hanging mass attached to a block on a table, with questions about the acceleration of the block and the minimum value of the coefficient of static friction needed for the block to remain motionless. The forces involved depend on the chosen coordinate system, with friction always acting in the opposite direction of motion. The second part of the problem involves statics, where all forces must balance. The ratio of the friction force to the normal reaction is called the coefficient of static friction.
  • #1
Raiden9
10
0
Hello, I deeply need help on this problem. ANY help would be appreciated.

Suppose a hanging 1.0 kb lab mass is attached to a 4.0 kg block on the table.
A) If the coefficent of kinetic friction, uk is 0.20, what is the accereration of the block?
B) What would be the minimun value of the coefficient of static friction, in order for the block to remain motionless?

I have my force diagrams made, equations also. What I am getting confused on is do I add the remaning unbalanced forces, Ff and Fg or is the Ff negative? Any help please!

Thank You!
 
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  • #2
The forces involved can be positive or negative depending on how you choose your coordinate system. For example, if you choose +y to be down, then mg is positive because it acts in the same direction as +y. The key to friction force is that it always acts in a direction opposite to motion. So, if you chose +x to be the direction the block on the table moves, then friction will be in the -x direction. The key is to be consistent with the coordinate system you decide to use.
 
  • #3
Oh I see. I have my axis as a traditional axis. So, I add my unbalanced forces according to the axis postive or negative values? I'm still stuck on the part b problem though, so any tad bit of help would help.
 
  • #4
Part b) is a statics problem. All the forces balance.

Have you got all the forces on the 4kg block ?
 
  • #5
Yes, I have the Fn y+, Fgy-, Ftx+, and Ffx-...
 
  • #6
Would I use the coefficient of kinetic friction from the last problem for the Ff in part b? I am really confused! Someone help please!
 
  • #7
It's now a statics problem! So the coefft of kinetic friction doesn't get involved. There's no movement.

What you have is limiting friction.
The block is static. When a force is applied to a static block, then there will always be static friction equal and opposite to the applied force on the block.
As the force increases, the static friction increases until the limiting condition is reached. The static friction reaches a maximum value and the block is just about ready to move. The ratio of this friction/applied force to the normal reaction is called the coefft of static friction.

This is the state that you have reached with the block. There is an applied force on the block. There is a static friction force opposing this. There is a normal reaction. That's all you need.
 
  • #8
I got it! Thanks!
 

What is the coefficient of static friction?

The coefficient of static friction is a measure of the force needed to overcome the resistance between two surfaces in relative motion.

How is the coefficient of static friction calculated?

The coefficient of static friction is calculated by dividing the maximum force of friction by the normal force between two surfaces. It is represented by the symbol μs.

Why is the coefficient of static friction important?

The coefficient of static friction is important because it helps determine the amount of force needed to keep an object at rest on a surface. It is also used in engineering and design to ensure the stability and safety of structures.

What factors affect the coefficient of static friction?

The coefficient of static friction can be affected by the materials of the two surfaces, the roughness of the surfaces, and the amount of force applied. It can also be affected by the presence of any lubricants or contaminants on the surfaces.

Can the coefficient of static friction be greater than one?

Yes, the coefficient of static friction can be greater than one. This means that a greater force is needed to overcome the resistance between two surfaces. However, it is rare for the coefficient of static friction to be greater than one in real-world situations.

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