Ok well here goes. what is teh chance of flipping a coin 10 times and getting either 10 heads or 10 tails. Once this is known, how many times would you expect to flip a coin before you get 10 in a row(I of course dont mean that after this number you would be guaranteed to get 10 in a row, i just mean statistically). here is what i'm thinking: the chance of flipping a coin 10 times and getting all heads or all tails would be 1 in 2^9. Since the first of the 10 flips doesnt really matter so it is only the remaining 9 that count. so you have a 1 in 512 chance that you will flip 10 of the same in a row. Now, to figure out how to how many flips it should take to get this result, i used the idea that you would need 512 groups of 10 flips to acheive this. to get 512 groups of 10 i would think that it would take 521 flips to acheive this, since: 11flips is essentially 2 chances at a group of 10(1-10, 2-11) 12 is 3 chances 13 is 4 chances 14 is 5 chances . . . 521 is 512 chances. Am I right in my logic?