- #1
pluspolaritons
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If I put a coin on a turntable at some distance away from the center and start turning the turntable eventually there will be a speed where the coin will fly off from the turntable.
If we put this into calculation. We will equate the centripetal force and static friction to find out the point where the coin will fly off.
Now my question is this. The centripetal force points to the center and the static friction points the opposite direction. If centripetal force overcomes the friction, it seems to suggest the force will point towards the center instead of radially outward. But by common sense we know that the coin will fly off instead of going to the center when the revolution speed is high enough. Can someone explain why the coin fly off instead of going to the center of the turntable?
Thanks.
If we put this into calculation. We will equate the centripetal force and static friction to find out the point where the coin will fly off.
Now my question is this. The centripetal force points to the center and the static friction points the opposite direction. If centripetal force overcomes the friction, it seems to suggest the force will point towards the center instead of radially outward. But by common sense we know that the coin will fly off instead of going to the center when the revolution speed is high enough. Can someone explain why the coin fly off instead of going to the center of the turntable?
Thanks.