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I was just wondering if you could help me, I seem to be having some problems getting to the correct answer (possibly because of my calculations). If two protons collide head on, both with energy 2keV... show that the closest approach is 7.2 x 10exp-11 cm. Now I know that when the protons are at closest approach then only the potential energy will be considered. Therefore V = q1q2 / r, which for a proton I know is e^2 / r, but for some reason I just cannot get to the right answer and I don't know if it is the way I am using electronvolts and joules. Please help.

Thanks

Greg

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# Homework Help: Colliding Protons

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