- #1
strawberry923
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1. Question: A 100g stone rests on a fricionless horizontal surface. A marble of mass 40g, traveling horizontantally at 30m/s strikes the stone and rebunds horizontally at right angles to its original direction wiht a speed of 20m/s. What is the velocity (magnitude and direction) of the stone after it has been struck? Can you see anything wrong with this question?
i think the relevant equations are: p = final momentum - initial momentum which is here 1,2 + 0,8 = 2 kgm/s
and to look for the velocity after it has been struck i used the formula p= 2kgm/s= (mA+mB).v so the v= 2:0,14 = 14,29, but think that's not the right formula and i don't know what's wrong with this question, i think its the "at right angles" bit, that confuses me the most... can someone pleaase help? :)
i think the relevant equations are: p = final momentum - initial momentum which is here 1,2 + 0,8 = 2 kgm/s
and to look for the velocity after it has been struck i used the formula p= 2kgm/s= (mA+mB).v so the v= 2:0,14 = 14,29, but think that's not the right formula and i don't know what's wrong with this question, i think its the "at right angles" bit, that confuses me the most... can someone pleaase help? :)