(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Ball 1 (B1) and Ball 2 (B2) are located at (x,y)=(0,0) and (x,y)=(d,h).

At t=0, B1 is sent towards the initial location of B2 with a speed vi. At the same

instant that B1 is launched, B2 falls towards the ground with zero initial velocity.

Assume there is no air resistance.

A diagram is attached below.

1. When and where do B1 and B2 collide?

2. If the initial speed of B1 is larger than vi, does a collision occur?

3. If B1 is directed towards a point slightly above the initial location of B2, can a

collision occur?

4. If B2 has an initial speed Vi in the negative y-direction, can B1 collide with B2?

2. Relevant equations

1. v_f = v_i + a[tex]\Delta[/tex]t

2. s_f = s_i +v[tex]\Delta[/tex]t +1/2a[tex]\Delta[/tex]t^2

3. v_f^2 = v_i^2 +2a[tex]\Delta[/tex]s

4. s_f = s_i + v[tex]\Delta[/tex]t

3. The attempt at a solution

Okay, I am really, really confused about this problem, but I tried #1.

I solved for the distance that Ball 1 travels using equation 4 and got:

s(ball 1) = cos[tex]\theta[/tex]v_it_1

Then for Ball 2 I used equation 2:

S(BALL 2) = h + 4.9t_1^2

Then I made both these equal each other:

h + 4.9t_1^2 - cos[tex]\theta[/tex]v_it_1 = 0

Now I know I can solve for time using quadratic formula but I'm not sure how to find where the balls meet. Also I am completely lost on how to solve for the rest of the questions. Please, someone help me out!! Any help is appreciated!

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# Homework Help: Collision of two Balls

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