A 5.4kg hawk flying swoops down at 65 degrees to the horizontal at 18m/s. The hawk grabs a pigeon flying 14 m/s horizontally. The pidgeon weighs 1.2kg. After the collision, what is the speed of the hawk (with the pidgeon) and at what angle to the horizontal is it now flying?
The equations used in this chapter were P=MV and MA1VA1+MB1VB1= MTVT
The Attempt at a Solution
I dont know how to solve this problem other than using sine and cosine formulas.
I multiplied the masses/velocities together to find kg*m/s and I found that the hawk had 97.2kg*m/s and the pigeon had 16.8kg*m/s
By using a^2=b^2+c^2 -2(b)(c)(cosA)
I found a resultant of 105.4kg*m/s. Dividing by the total mass (6.6kg) I found a total velocity of 15.97m/s.
Then, to find the angle, I used law of sines.
105.4/sin115 = 16.8/sinX == 8.3 degrees
Add 25 degrees to make up for the hawk's dive. So that ends up being 33.3degrees.
So...can I have help verifying this?