1. The problem statement, all variables and given/known data A football player weighing 71 kg running at 2.1 m/s sacks a stationary quarterback who weighs 52 kg. How far will the two move after the collision if the coefficient of friction between the cleats and ground is 0.052. 2. Relevant equations m1v1' + m2v2' = mv'1 uk = Fk / Fn 3. The attempt at a solution m1v1' + m2v2' = mv'1 (m1v1' + m2v2') / m = v'1 v'1 = 71 * 2.1 / 123 v'1 = 1.212 m/s uk = Fk/Fn Fk = Fnuk Fk = 123 * 9.8 * 0.052 Fk = 62.68 N Providing I did this right, I now have the speed they move after they are together and the friction in N. From here I am not sure how to calculate the distance they will move. Could somebody give me a hand?