ice hockey puck moving at speed V1 collides head on with a second identical puck moving towards it at speed V2. After the collision, the first puck slows down to speed v1 without changing direction.
a)After the collision what is the speed v2 of the second puck?
b) calculate the speed v2 of the second puck when the first puck had an initial speed of 18ms-1 that was changed to 2.0ms-1 by the collision, and the initial speed of the second puck was 12,0ms-1. both pucks have a mass of 0.16kg
The Attempt at a Solution
well the questions shows that the initial puck continues on its path at a lower speed to i guess this was an elastic collision
not sure if the math is right tho
m1V1+m2V2 = m1v1+m2v2
v2 = m1V1+m2V2/m1v1 + m2
when i factor in the given speeds and masses in the next part of the question i am not sure if it is right.
v2 = (0.16kg)(18.oms-1)+(0.16kg)(12.0ms-1)/(0.16kg)(2.0ms-1)+0.16kg
v2 = 15.16ms-1
is this right???