Collisions homework problem

1. pinkyjoshi65

263
A 1.0 kg magnetized air puck moving across a level table at 0.24 m/s approaches head-on a stationary, similarly magnetized air puck of mass 0.50 kg. If the "magnetic collision" is repulsive and perfectly elastic, determine:
(a) the velocity of each puck after the collision
(b) the velocity of both pucks at minimum separation
(c) the total kinetic energy at minimum separation
(d) the maximum potential energy stored in the magnetic force field during the collision

For A) i simply used the conservation of momentum and KE and found the final velocities (1-dimensional)

For B) I am not sure how to find th miniimum distance

Staff: Mentor

Hint: When the pucks are as close to each other as they get, what's the relationship of their velocities?

3. pinkyjoshi65

263
uhh..i am not sure abt this..velocities become the same..?

Staff: Mentor

Exactly! (If the velocities weren't the same, then they'd keep getting closer.) So figure out what that velocity must be.

5. pinkyjoshi65

263
so you are saying that the collision becomes the case of a perfectly inelastic collision...?

6. pinkyjoshi65

263
if thats the case, then M1v= (M1+M2)V
hence V= M1v/M1+M2

Exactly.

8. pinkyjoshi65

263
ahh k..so for part c its quite staight foreward. we have to use0.5(M1+M2)V2
For part d potential enegy will be max when the h is max. How do we find the h..?

9. pinkyjoshi65

263
and also this is all 1-dimensional yes?

Staff: Mentor

Right.
What do you mean by "h is max"? Just use the fact that total energy is constant.

11. pinkyjoshi65

263
so then the potential energy will be equal to the kE in part C)..?

Staff: Mentor

No, but the sum of PE + KE must be constant. (What's the initial total energy?)

13. pinkyjoshi65

263
initial total energy is M1v1^2+ M2v2^2

Staff: Mentor

Not exactly. Initially, only one puck is moving. (And that's not the correct formula for KE!)

15. pinkyjoshi65

263
yes so M2v2^2 will 0..i know that hence the initial total energy will be 0.5*M1v1^2= 0.0288J. so then we can subtract the KE (from part c)frm this energy to find the PE

Staff: Mentor

Now you've got it.