(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Billiard ball A of mass mA= 0.400kg moving with speed vA=1.80m/s strikes ball B initially at erst, of mass mB=0.500kg.As a result of the collision,ball A is deflected off at an angle of 30.0degrees with a speed v'A=1.10m/s. Taking the x-axis as the original direction of motion of ball A, solve for the speed v'B and angle Θ'B of ball B. Do not assume the collision is elastic.

2. Relevant equations

px conserved: mAvA=mAv'ACosΘ'A+mBv'BCosΘ'B

py conserved: mAvA=mAv'AsinΘ'A+mBv'BSinΘ'B

3. The attempt at a solution

0.72=0.38105+0.500v'BCosΘ'B

0.338948/0.500=v'BCosΘ'B

0.677897=v'BCosΘ'B

0.677897/CosΘ'B= v'B

0=mAv'AsinΘ'A+mBv'BSinΘ'B

0=0.22+0.5v'BSinΘ'B

-0.22/0.5=v'BSinΘ'B

-0.44=v'BSinΘ'B

-0.44=(0.677897/CosΘ'B)SinΘ'B

-1.5407=CosΘ'BSinΘ'B

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# Homework Help: Collisions in two dimensions

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