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## Homework Statement

Billiard ball A of mass mA= 0.400kg moving with speed vA=1.80m/s strikes ball B initially at erst, of mass mB=0.500kg.As a result of the collision,ball A is deflected off at an angle of 30.0degrees with a speed v'A=1.10m/s. Taking the x-axis as the original direction of motion of ball A, solve for the speed v'B and angle Θ'B of ball B. Do not assume the collision is elastic.

## Homework Equations

px conserved: mAvA=mAv'ACosΘ'A+mBv'BCosΘ'B

py conserved: mAvA=mAv'AsinΘ'A+mBv'BSinΘ'B

## The Attempt at a Solution

0.72=0.38105+0.500v'BCosΘ'B

0.338948/0.500=v'BCosΘ'B

0.677897=v'BCosΘ'B

0.677897/CosΘ'B= v'B

0=mAv'AsinΘ'A+mBv'BSinΘ'B

0=0.22+0.5v'BSinΘ'B

-0.22/0.5=v'BSinΘ'B

-0.44=v'BSinΘ'B

-0.44=(0.677897/CosΘ'B)SinΘ'B

-1.5407=CosΘ'BSinΘ'B