A uniform rod of length L1 = 2.2 m and mass M = 2.8 kg is supported by a hinge at one end and is free to rotate in the vertical plane. The rod is released from rest in the position shown. A particle of mass m is supported by a thin string of length L2 = 1.8 m from the hinge. The particle sticks to the rod on contact. After the collision, θmax = 40°. (a) Find m. kg (b) How much energy is dissipated during the collision? J Relevant Equations: Angular momentum = I * omega I'm having trouble starting this problem. I should compare using energy of conservation before and after collision correct? I for the thin rod = 1/3 ML^2 Energy of conservation for the rod before collision Kf - Ki + Uf - Ui = 0 Ki = 0 Kf + Uf - Ui = 0 1/2(1/3ML^2) * omega ^2 + Uf - Ui = 0 What will Uf and Ui be? Im not even sure if what Im doing is correct, can someone guide me?