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Coloumb Help

  1. Sep 2, 2006 #1

    Four charges are placed on the corners of a rectangle. What is the resultant force on the positive charge (a = 1.1 m, b = 0.7 m, q = 2.4 × 10-9C)?

    So you need to break this into X and Y, for Hypotnuse i got 1.303

    So wat i did was

    Ex1 = K(2.4*10^-9) * Cos 32.47 / (1.303)^2 = 10.286

    EY1 = K * 2.3*10^-9 * sin 32.47 / (1.303)^2 = 6.545

    For Ex2 and Ey2, the answers should be the same

    I am trying to find |F| , i know after i get Ex and Ey i will multiply this by 2.4*10^-9 and do X^2+Y^2 and take the square root

    How do i get F. Thanks
  2. jcsd
  3. Sep 3, 2006 #2
    You've apparently found the X-Y components of the force due to the
    charge at the opposite corner of the rectangle. Just add these
    components to the X-Y components of the forces due to the charges at the adjacent corners of the rectangle. Then find the resultant of the total X-Y components of the forces just found.
  4. Sep 3, 2006 #3

    Ex = K(2.4*10^-9) (1.1)^2= 17.851

    EY = K * 2.4*10^-9 / (.7)^2 = 44.081
    Last edited: Sep 3, 2006
  5. Sep 3, 2006 #4
    Hw is due in an hour, i have tried everything
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