Coloumb Help

1. Sep 2, 2006

Alt+F4

Four charges are placed on the corners of a rectangle. What is the resultant force on the positive charge (a = 1.1 m, b = 0.7 m, q = 2.4 × 10-9C)?

So you need to break this into X and Y, for Hypotnuse i got 1.303

So wat i did was

Ex1 = K(2.4*10^-9) * Cos 32.47 / (1.303)^2 = 10.286

EY1 = K * 2.3*10^-9 * sin 32.47 / (1.303)^2 = 6.545

For Ex2 and Ey2, the answers should be the same

I am trying to find |F| , i know after i get Ex and Ey i will multiply this by 2.4*10^-9 and do X^2+Y^2 and take the square root

How do i get F. Thanks

2. Sep 3, 2006

J Hann

You've apparently found the X-Y components of the force due to the
charge at the opposite corner of the rectangle. Just add these
components to the X-Y components of the forces due to the charges at the adjacent corners of the rectangle. Then find the resultant of the total X-Y components of the forces just found.

3. Sep 3, 2006

Alt+F4

Ex = K(2.4*10^-9) (1.1)^2= 17.851

EY = K * 2.4*10^-9 / (.7)^2 = 44.081

Last edited: Sep 3, 2006
4. Sep 3, 2006

Alt+F4

Hw is due in an hour, i have tried everything